Sunday, September 2, 2012
Antimatter Positrons in Banana, Yam, and Plantain
· Potassium-40 is a naturally occurring isotope that is unstable and radioactively decays.
· The radioactive half-life of Potassium-40 is 3.938×1016 seconds.
· The atomic mass of Potassium is 39.1 g/mol.
· When Potassium-40 radioactively decays, 1 in every 100,000 decays emits an Anti-Electron or Positron particle of Antimatter.
· For every 1,000,000 atoms of Natural Potassium, about 117 atoms are Potassium-40.
· Therefore, substances dense with Potassium will likely contain Potassium-40 and will also occasionally emit Antimatter in the form of an Anti-Electron.
Bananas are food that is rich with Potassium. Let’s calculate the Anti-matter emitted by an Average Banana.
· 1 Average Banana contains 0.450 grams of Natural Potassium
= 0.450 g × (6.02×1023) atoms/mol ÷ 39.1 g/mol = 6.93×1021 atoms of Potassium
Remember that for every 1,000,000 atoms of Natural Potassium, about 117 atoms are Potassium-40. So to find the number of atoms of Potassium-40 in our Potassium atoms we
= (117 ÷ 1,000,000) × 6.93×1021 atoms = 8.11×1017 atoms of Potassium-40
To find out how many decays of Potassium-40 occur per second, we divide our total number of Potassium-40 atoms by the radioactive half-life of Potassium-40 which is 3.938×1016 seconds
= 8.11×1017 atoms of Potassium-40 ÷ 3.938×1016 seconds = 20.58 decays of Potassium-40 per second
· Now remembering that 1 in every 100,000 decays of Potassium-40 emits a Positron particle of Antimatter, then we can calculate how often a Positron particle of Antimatter is emitted from our banana by
= (100,000 decays ÷ 20.58 decays per sec.) ÷ 60 sec. per min.
= Every 81 minutes an Anti-Electron Antimatter particle is emitted from a Banana
Yam and Plantain are two foods common in African and Caribbean diets which are higher in Potassium content than Banana. Let’s use the formulas provided to calculate how long it will take for the African Yam and Plantain to emit a Positron particle of Antimatter.
· 1 Average Plantain contains 0.534 grams of Natural Potassium
= 0.534 g × (6.02×1023) ÷ 39.1 = 8.22×1021 atoms of Potassium
= (117 ÷ 1,000,000) × 8.22×1021 = 9.62×1017 atoms of Potassium-40
= 9.62×1017 ÷ 3.938×1016 = 24.43 decays of Potassium-40 per second
= (100,000 decays ÷ 24.43 decays per sec.) ÷ 60 sec. per min.
= Every 68 minutes an Anti-Electron Antimatter particle is emitted from a Plantain
· 1 Average African Yam contains 0.694 grams of Natural Potassium
= 0.694 g × (6.02×1023) ÷ 39.1 = 10.7×1021 atoms of Potassium
= (117 ÷ 1,000,000) × 10.7×1021 = 12.5×1017 atoms of Potassium-40
= 12.5×1017 ÷ 3.938×1016 = 31.75 decays of Potassium-40 per second
= (100,000 decays ÷ 31.75 decays per sec.) ÷ 60 sec. per min.
= Every 53 minutes an Anti-Electron Antimatter particle is emitted from an African Yam
Jamaican sprinter Yohan Blake eats 16 Bananas per day. There are 1440 minutes in a day; therefore, Yohan Blake takes in about 18 Positron Antimatter particles per day just from eating Bananas. Perhaps the consumption of the Anti-matter found in Yam, Plantain, and Banana is what has led to the superior performance of Yohan Blake, Usain Bolt, and the other Jamaican sprinters in this year’s Olympic Games.
For this and other African science experiments, be sure to check out the book “9Ether RE Engineering”, and for recipes on how to prepare African Yam and Plantain, be sure to check out the book “Back To Our Roots, Food for the Gods” both available at www.AfricanCreationEnergy.com